7p^2-p-4=0

Solution for 7p^2-p-4=0 equation:

7p^2-p-4=0

We add all the numbers together, and all the variables

7p^2-1p-4=0

a = 7; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·7·(-4)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{113}}{2*7}=\frac{1-\sqrt{113}}{14}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{113}}{2*7}=\frac{1+\sqrt{113}}{14}
$